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Time required to deposit one mill mole of aluminium metal by the passage of 9.65 amperes through aqueous solution of aluminum ions is

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30s

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10,000s

answer is A.

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Detailed Solution

i=9.65amp t=?

$10^{- 3} milli moles of Al = 27 x 10^{- 3} g$

${Al}^{+ 3} + 3 F \to Al$

$3 F \to 27 g$

$1 mole \to 27 g$

$1 milli mole \to 27 x 10^{- 3} g$

$Z = \frac{E}{F}$

$Z = \frac{27}{3 F}$

m=Zit

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