Q.

Time taken by light to travel in two different materials A and B of refractive indices  μA and μB of same thickness is t1 and t2 respectively. If t2t1=5×1010 s and the ratio of μA to μB is 1 : 2. Then the thickness of material, in meter is : (Given vA and vB are velocities of light in A and B materials respectively).

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a

5×1010 vBm

b

5×1010 m

c

5×1010 vAm

d

1.5×1010 m

answer is A.

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Detailed Solution

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μAμB=c/VAc/VB=VBVA=12

Let the thickness is d

dvBdvA=5×1010d=5×1010×vAvBvAvB As vA=2vBd=5×1010×2vB Or d=5×1010×vA

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