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To a 10 mL of 10^-3N H₂SO₄ solution water has been added to make the total volume of one litre. Its pOH would be :

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answer is C.

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Detailed Solution

$N_{1} V_{1} = N_{2} V_{2} 10^{- 3} \times 10 = N_{2} \times 1000 \Rightarrow N_{2} = 10^{- 5} ∴ pH = 5 and pOH = 14 - 5 = 9$

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