To a 100 g an oleum sample labelled as ‘118% oleum’, 9g of water is added. Select the correct option(s).

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It contains only $H_{2} S O_{4}, S O_{3} a n d S O_{2}$

It contains $H_{2} S O_{4}, S O_{3} a n d H_{2} O .$

New solution will have labelling 109%

% w/w of $S O_{3}$ is nearly 36.7%

answer is D.

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Detailed Solution

118% oleum means in 100g oleum by adding 18g water it gives 118g $H_{2} S O_{4} n_{H_{2} O}$ added $= n_{S O_{3}}$ Present in 100g oleum by adding 9g or $\frac{1}{2}$ mole water $\frac{1}{2}$ mole $S O_{3}$ change into $H_{2} S O_{4}$ and mole $S O_{3}$ = 40g $S O_{3}$ present in 109g oleum
$∴ % w t o f S O_{3} = \frac{40}{109} \times 100 = 36.7 %$