To a fish in water, a bird in air appears to be at 30 cm from the surface. If aμw=43, then the true distance of the bird from the surface is.

d'd=μ2μ1 30d=43×1 ⇒d=22.5 cm

To a fish in water, a bird in air appears to be at 30 cm from the surface. If aμw=43, then the true distance of the bird from the surface is.

d'd=μ2μ1 30d=43×1 ⇒d=22.5 cm

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To a fish in water, a bird in air appears to be at 30 cm from the surface. If $_{a} μ_{w} = \frac{4}{3},$ then the true distance of the bird from the surface is.

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22.5 cm

80 cm

30 cm

40 cm

answer is B.

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Detailed Solution

$\frac{d^{'}}{d} = \frac{μ_{2}}{μ_{1}}$

$\frac{30}{d} = \frac{4}{3 \times 1}$

$\Rightarrow d = 22.5 c m$

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To a fish in water, a bird in air appears to be at 30 cm from the surface. If aμw=43, then the true distance of the bird from the surface is.

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To a fish in water, a bird in air appears to be at 30 cm from the surface. If $_{a} μ_{w} = \frac{4}{3},$ then the true distance of the bird from the surface is.