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Q.

To a given container having a pore of definite size, gas A (mol. wt. = 81) is filled till the final pressure become 10 atm. It was seen that in 50 minutes 10 g of A was effused out. Now the container was completely evacuated and filled with gas B (mol. wt = 100) till the final pressure becomes 20 atm. In 75 minutes how many gram of B will be effused out ?

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a

1003g

b

2003g

c

1006g

d

2503g

answer is B.

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Detailed Solution

 

Gas AGas B
WA=10 gmWB=?
MA=81MB=100
PA=10 atmPB=20 atm
tA=50 mintB=75 min

wAwB×tAtB=PAPBMAMB

On putting all values

10 ×75WB ×50=102081100=10 ×920  × 10=920

750WB ×50=920 ; WB=750×2050 ×9=3009=1003g

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