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To break a wire of one meter length, minimum 40 kgwt is required then the wire of same material of double radius and 6 m length will require a breaking weight of

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80 kgwt

240 kgwt

200 kgwt

160 kgwt

answer is D.

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Detailed Solution

Breaking force $\propto$ area of cross-section and independent of length

$F_{2} = F_{1} \times {(\frac{r_{2}}{r_{1}})}^{2}$ $= 40 \times \frac{4 r^{2}}{r^{2}} = 160 k g w t$

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