To construct a triangle similar to △𝐴𝐵𝐶 with its side $\frac{8}{5}$ of the corresponding 
sides of △𝐴𝐵𝐶 draw a ray 𝐵𝑋 such that ∠𝐶𝐵𝑋 is an acute angle and 𝑋 is on the opposite side of 𝐴 with respect to 𝐵𝐶. The minimum number of points to be located at equal distances on
the ray 𝐵X:

To construct a triangle similar to a given triangle with its sides 𝑚/𝑛
(𝑚 > 𝑛) of the corresponding sides of given  triangle, the minimum number of points to be located at equal distances is equal to the maximum of 𝑚 and 𝑛 in $\frac{m}{n}$.

Here, $\frac{m}{n} = \frac{8}{5}$

So, the minimum number of points to be located at equal distance on ray 𝐵𝑋 is 8.
Hence, option (b) 8 is correct.