To convert a 800 mV range milli-voltmeter of resistance 40 $Ω$ into a milli ammeter of 100 mA range, the resistance to be connected as shunt is,

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1 $Ω$

5 $Ω$

10 $Ω$

2.5 $Ω$

answer is A.

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Detailed Solution

$\begin{array}{l} i_{g} = \frac{800 \times 10^{- 3}}{40} = 20 \times 10^{- 3} A \\ \frac{i_{g}}{i} = \frac{S}{G + S} \Rightarrow \frac{20 \times 10^{3}}{100 \times 10^{- 3}} = \frac{S}{40 + S}; S = 10 Ω \end{array}$

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