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Q.

To convert a galvanometer to ammeter a shunt S is to be connected with the galvanometer. The effective resistance of the ammeter then is

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a

GS/(G+S)

b

(G+S)/GS

c

None of the above

d

G+S

answer is A.

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Detailed Solution

Shunt (S) is connected in parallel to the galvanometer (resistance G). So, the effective resistance is GS/(G+S).

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