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Q.

To deposit one mole each of Ag, Cu and Al from fused ${AgNO}_{3}, {CuSO}_{4}$ and ${AlCl}_{3}$ , the number of faradays required will be in the ratio

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a

1 : 1 : 1

b

1 : 3 : 1

c

3 : 2 : 1

d

1 : 2 : 3

answer is B.

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Detailed Solution

$\begin{array}{l} {Ag}^{+} + e^{-} \to Ag \\ {Cu}^{2 +} + 2 e^{-} \to Cu \\ {Al}^{3 +} + 3 e^{-} \to Al \end{array}$

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