To estimate g (from g=4π2LT2), error in measurement of L is ±2% and error in measurement of T is ±3%. The error in estimated g will be

g=4π2lT2Δgg=Δll+2ΔTT=2+2×310-2=8×10-2 Δgg×100=±8%

To estimate g (from g=4π2LT2), error in measurement of L is ±2% and error in measurement of T is ±3%. The error in estimated g will be

g=4π2lT2Δgg=Δll+2ΔTT=2+2×310-2=8×10-2 Δgg×100=±8%

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To estimate $g$ (from $g = 4 π^{2} \frac{L}{T^{2}}$ ), error in measurement of $L$ is $\pm 2 %$ and error in measurement of $T is \pm 3 %$ . The error in estimated $g$ will be

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± 6 %

± 5 %

± 8 %

± 3 %

answer is A.

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$g = 4 π^{2} \frac{l}{T^{2}}$

$\frac{Δg}{g} = \frac{Δl}{l} + \frac{2 ΔT}{T} = (2 + 2 \times 3) 10^{- 2} = 8 \times 10^{- 2} \frac{Δg}{g} \times 100 = \pm 8 %$

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To estimate g (from g=4π2LT2), error in measurement of L is ±2% and error in measurement of T is ±3%. The error in estimated g will be

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To estimate $g$ (from $g = 4 π^{2} \frac{L}{T^{2}}$ ), error in measurement of $L$ is $\pm 2 %$ and error in measurement of $T is \pm 3 %$ . The error in estimated $g$ will be