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To get an OR gate from a NAND gate we need :

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only 4 NAND gates.

two NOT gates obtained from NAND gates and one NAND gate.

4 NAND gates and 2 AND gates obtained from NAND gate.

3 NAND gates and 3 NOT gates obtained from NAND gates.

answer is B.

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Detailed Solution

OR gate can be obtained as

$\bar{\bar{A} \bar{B}} = Y T w o N A N D g a t e s g i v e s \bar{A} a n d \bar{B} a n d a n o t h e r N A N D g a t e w i l l g i v e \bar{\bar{A} \bar{B}} w h i c h i s A + B .$

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