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Q.

To get maximum current in a resistance of $3 Ω$ one can use n parallel rows of m cells each (connected in series). If the total no.of cells is 24 and the internal resistance is 0.5ohm, then

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a

$m = 8, n = 3$

b

$m = 12, n = 2$

c

$m = 6, n = 4$

d

$m = 2, n = 12$

answer is A.

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Detailed Solution

$\begin{array}{l} \frac{mr}{n} = 3 \Rightarrow \frac{m \times 0 .5}{n} = 3 \Rightarrow \frac{m}{n} = 6 \overset{}{\to} (1) \\ mn = 24 \overset{}{\to} (2) \\ from (1) & (2) \\ 6 n = \frac{24}{n} \Rightarrow n^{2} = 4 \\ ∴ n = 2 & m = 12 \end{array}$

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