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To go from town A to town B a plane must fly about 1780 km at an angle of $30 °$ west of north. How far north of A is B?

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1452 km

11 km

1254 km

1542 km

answer is A.

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Detailed Solution

From $Δ A D B$

$\sin 60 = \frac{B D}{A B}$

$B D = A B \sin 60^{0}$

$B D = 1780 \times \frac{\sqrt{3}}{2} = 1542 k m$

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