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Q.

To verify Ohm’s law, a student connects the voltmeter across the battery as, shown in the figure. The measured voltage is plotted as a function of the current, and the following graph is obtained.

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If V0 is almost zero, identify the correct statement.

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a

The potential difference across the battery is 1.5V when it sends a current of 1000 mA

b

The value of the resistance R is 1.5Ω

c

The emf of the battery is 1.5 V and its internal resistance is 1.5Ω

d

The emf of the battery is 1.5 V and the value of R is 1.5Ω

answer is D.

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Detailed Solution

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V=E-I R

 When, I=O,V=E=1.5 V

I=1000 mA, V=0

∴1.5-1×r=0⇒r=1.5Ω

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