To $500 {\mathrm{cm}}^3$ of water, $3.0 \mathrm{x} {10}^{-3} \mathrm{kg}$ of acetic acid is added. If 23% of acetic acid is dissociated, what Will be the depression in freezing point? Kr and density of water are $1.86\mathrm{K} \mathrm{kg} {\mathrm{mole}}^{-1}$  and $0.997 \mathrm{g} {\mathrm{cm}}^{-3}$ respectively

Depression in Freezing point is a colligative  property observed  in solutions that results from the introduction of solute molecules to a solvent.

Another formula is ,

$\mathrm{\Delta }{T}_f=i{k}_{f}m$                     i=Van't Hoff factor

$\begin{array}{l}\mathrm{\Delta }{T}_f=(1+0.23)\times 1.86\times \left[\frac{\frac{3\times {10}^{-3}\times {10}^3}{60}}{500\times 0.997}\right]\times 1000\\ =0.229\mathrm{K}\end{array}$