Q.

To generate a power of 3.2 mega watt, the number of fissions of U235 per minute is

(Energy released per fission = 200 MeV, 1 eV= 1.6 x 10-19J )

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a

6 x 1018

b

6 x 1017

c

1017

d

6 x 1016

answer is A.

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Detailed Solution

Number of fissions per second

=Power outputEnergu released per fission

=3.2 x 106200 x 106 x 1.6 x 10-19=1 x 1017

Number of fission per minute

=60 x 1 x 1017=6 x 1018

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