$\mathrm{Toluene}\underset{△}{\overset{{\mathrm{KMnO}}_4+\mathrm{KOH}}{\to }}\mathrm{A}\stackrel{{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }\mathrm{C}.\mathrm{n}–\mathrm{propyl} \mathrm{benzene} \underset{△}{\overset{{\mathrm{KMnO}}_4+\mathrm{KOH}}{\to }}\mathrm{P}\stackrel{{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }\mathrm{Q}.$ Correct statement is 

C and Q are benzaldehyde

A and P are different and C and Q are different

A and P are same and C and Q are same

A and P are different but C and Q are same