Q.

Total number of ‘σ ’ bonds present in [B4O5(OH)4]2- ion is

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a

16

b

14

c

20

d

18

answer is C.

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Detailed Solution

The structure of [B4O5(OH)4]2- is given below:

Question Image

There are 18 sigma bonds in [B4O5(OH)4]2-.

Therefore, the correct option is (C).

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