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Q.

Total number of acyclic isomers possible with the formula, C5H10 is ‘X’. Total number of cyclic optical isomers possible with the formula, C5H10 is ‘Y’. Difference between X and Y is

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a

6

b

3

c

4

d

5

answer is C.

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Detailed Solution

(1)Number of structurally isomeric alkenes = 5 ;

(2)Number of structurally isomeric cycloalkanes = 5 ;

(3)Number of structural isomers = 10 ;

(4)Number of acyclic stereo isomers = 2 ;

cis 2-pentene and trans 2-pentene ;

(5)Number of cyclic stereo isomers = 3 ;

cis 1,2-dimethyl cyclopropane(meso) and trans 1,2-dimethyl cyclopropane(d and l) ;

(5)Number of stereoisomers = 5 ;

(6)Number of acyclic isomers = 6 ;

(7)Number of cyclic isomers = 7 ;

(8)Total number of isomers =13 ;

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