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Total number of electrons present in 48g of ${Mg}^{2 +}$ is:

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$24 N_{A}$

$12 N_{A}$

$2 N_{A}$

$20 N_{A}$

answer is C.

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Detailed Solution

Mg atomic number is 12 and molar mass is 24g/mol.

Therefore, $M g^{2 +}$ ion has:

10 electrons 48 g Mg²⁺ = 48/24 = 2 mol

Number of ions in 48g

Mg²⁺ =2 $\times$ N_A

number of electrons $= 2 \times N_{A} \times 10 = 20 N_{A}$

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