Q.

Total number of electrons present is 4.4 gm oxalate ion C2O42 is:

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a

0.05NA

b

2.1NA

c

2.3NA

d

2.2NA

answer is B.

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Detailed Solution

Total number of electron,

=4.488×[6×2+8×4+2]×NA
=2.3NA.

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