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Q.

Total number of protons, neutrons and electrons present in $14 mg$ of $_{6} C^{14}$ is:
$(Take N_{A} = 6 \times 10^{23})$

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a

$1.2 \times 10^{25}$

b

$1.2 \times 10^{22}$

c

$1.08 \times 10^{22}$

d

$7.2 \times 10^{21}$

answer is A.

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Detailed Solution

Total number of protons, neutrons and electrons presen,

$\frac{14 \times 10^{- 8}}{14} \times 20 \times 6 \times 10^{23}$

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Total number of protons, neutrons and electrons present in 14mg of 6C14 is: Take NA=6×1023