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Q.

Total number of species in which highest occupied molecular orbital has grade type of symmetry.
$B_{2}, N_{2}, C_{2}, N_{2}^{2 +}, O_{2}, O_{2}^{2 -}, N_{2}^{2 -}$ .

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answer is 4.

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Detailed Solution

Here,

	HOMO	Symmetry
$B_{2}$	$π 2 p_{x} = π 2 p_{y}$	u
$N_{2}$	$σ 2 p z$	g
$C_{2}$	$π 2 p_{x} = π 2 p_{y}$	u
$N_{2}^{2 +}$	$π 2 p_{x} = π 2 p_{y}$	u
$O_{2}$	$π * 2 p_{x} = π * 2 p_{y}$	g
$O_{2}^{2 -}$	$π * 2 p_{x} = π * 2 p_{y}$	g
$N_{2}^{2 -}$	$π * 2 p_{x} = π * 2 p_{y}$	g

The species in which highest occupied molecular orbital has grade type of symmetry are 4

Thus, the correct answer is 4.

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Total number of species in which highest occupied molecular orbital has grade type of symmetry.B2,N2,C2,N22+,O2,O22−,N22−.