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Q.

Total surface area of a narrow hemisphere of external and internal radii R and r is given by

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a

π (R^{2} + 3 r^{2})

b

3 π (3 R^{2} + 3 r^{2})

c

π (3 R^{2} + r^{2})

d

π (3 R^{2} + 3 r^{2})

answer is C.

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Detailed Solution

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T.S.A $= 2 π R^{2} + π (R^{2} - r^{2}) + 2 π r^{2}$

$= 2 π R^{2} + π R^{2} - π r^{2} + 2 π r^{2}$

$= 3 π R^{2} + π r^{2}$

$= π (3 R^{2} + r^{2})$

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