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Total volume of atoms present in a facecentred cubic unit cell of a metal is ( r is atomic radius)

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$\frac{{16}}{3}\pi {r^3}$

$\frac{{20}}{{\sqrt 3 }}\pi {r^3}$

$\large \frac{{12}}{3}\pi {r^3}$

$\frac{{24}}{3}\pi {r^3}$

answer is B.

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Detailed Solution

FCC unit cell contains 4 atoms.

Volume of 4 atoms= 4 x 4/3 x $π$ x r³= 16/3 x $π$ x r³

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