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Q.

Trajectories of two projectiles are shown in figure, let T₁ and T₂ be the periods and u₁ and u₂ are their speeds of projections, then [UP CPMT 2012]

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a

$T_{2} > T_{1}$

b

$T_{1} = T_{2}$

c

$u_{1} > u_{2}$

d

$u_{1} < u_{2}$

answer is D.

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Detailed Solution

$H_{1} > H_{2}$

$u_{1} \sin α_{1} > u_{2} \sin α_{2} S i n c e α_{1} > α_{2} w e c o n c l u d e u_{1} < u_{2}$

Also T = $\frac{2 u \sin α}{2}$ .

Since $u_{1} \sin α_{1} > u_{2} \sin α_{2}, w e c a n c o n c l u d e T_{1} > T_{2}$

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