Trajectories of two projectiles are shown in figure. Let $T_{1}$ and $T_{2}$ be the time periods and $u_{1}$ and $u_{2}$ their speeds of projection. Then

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$T_{2} = T_{1}$

$u_{1} > u_{2}$

$u_{2} > u_{1}$

$T_{2} > T_{1}$

answer is B, D.

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Detailed Solution

Maximum height and time of flight depend on the vertical component of initial velocity.

$H_{1} = H_{2} \Rightarrow u_{y 1} = u_{y 2}$ ; Hence $T_{1} = T_{2}$

Range $R = \frac{u^{2} \sin 2 α}{g} = \frac{2 (u \sin α) (u \cos α)}{g} = \frac{2 u_{x} u_{y}}{g}$

$R_{2} > R_{1} ∴ u_{x_{2}} > u_{x_{1}} o r u_{2} > u_{1}$

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