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Transition metal ions can be detected with the help of Borax bead test. Formula and colour of the bead formed by Cobalt (II) compounds in this test will be

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${Co}_{3} {({BO}_{3})}_{2}$ , Blue

$Co {({BO}_{2})}_{3}$ , Green

${CoB}_{4} O_{7},$ Green

$Co {({BO}_{2})}_{2}$ , Blue

answer is D.

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Detailed Solution

${Na}_{2} B_{4} O_{7} . 10 H_{2} O \overset{∆}{\to} {Na}_{2} B_{4} O_{7} \overset{fuse}{\to} \underset{colour less glassy bead}{{NaBO}_{2} + B_{2} O_{3}}$

$CoO + B_{2} O_{3} \overset{}{\to} \underset{Blue}{Co {({BO}_{2})}_{2}} .$

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