Tri-iodide ion has a linear symmetry with bond-angle of 180°. In the structure of $I_{3}^{-}$ ion :

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$I_{2}$ acts as a lewis base and $I^{-}$ as a lewis acid

both $I_{2}$ and $I^{-}$ as a lewis base

both $I_{2}$ and $I^{-}$ as a lewis acid

$I_{2}$ acts as a lewis acid while $I^{-}$ as a lewis base

answer is A.

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Detailed Solution

Geometry of the $I_{3}$ molecule is linear. Three iodine atoms make up the compound, but because one of them has a negative charge, there are 3 lone pairs of electrons and 2 bond pairs. It will have a steric number of 5. The three lone couples will move into equatorial positions and repel one another.

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