Q.

Triangle  ABC  has side lengths AB=7,BC=8  and CA=9.  Circle  ω1 passes through  B and is tangent to line AC  at A.  Circle  ω2 passes through C  and it tangent to line AB  at A.  Let K  be in the intersection of circles  ω1 and  ω2 ( K is different from  A). Then  AK=mn, where  m and n  are relatively prime positive integers. The value of  mn is equal to _____

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answer is 7.

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Detailed Solution

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Note that from the tangency condition that the supplement of  CAB  with respects to lines AB  and AC  are equal to AC  and  AKC, respectively, so from tangent chord, AKC=AKB=180°BAC

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