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Trioxalato aluminate (III) and tetrafluoro-borate (III) ions are

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$[Al {(C_{2} O_{4})}_{3}], {[B F_{4}]}^{- 3}$

${[Al {(C_{2} O_{4})}_{3}]}^{+ 3}, {[B F_{4}]}^{- 3}$

${[Al {(C_{2} O_{4})}_{3}]}^{- 3}, {[B F_{4}]}^{-}$

${[Al {(C_{2} O_{4})}_{3}]}^{- 2}, {[B F_{4}]}^{- 2}$

answer is C.

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${[Al {(C_{2} O_{4})}_{3}]}^{- 3}, {[B F_{4}]}^{-}$

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