Tuning fork A of frequency 258 Hz gives 8 beats with a tuning fork B. When the tuning fork A is filed and again A and B are sounded the number of beats heard decreases. The frequency of B is

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Tuning fork A of frequency 258 Hz gives 8 beats with a tuning fork B. When the tuning fork A is filed and again A and B are sounded the number of beats heard decreases. The frequency of B is

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250 Hz

266 Hz

258 Hz

242 Hz

answer is B.

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Detailed Solution

n_A = 258Hz ; n = 8b/s
n_A will increase on filing, So the frequency gets closer to n_B.( Since the number of beats decreases).

So n_B>n_A $\Rightarrow$ n_B = n_A - n = 258 + 8 =266 Hz

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