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Twelve tickets are numbered from 1 to 12. One ticket is drawn at random, then the probability of the number to be divisible by 2 or 3 is

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$2 / 3$

$7 / 12$

$3 / 4$

$5 / 6$

answer is A.

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Detailed Solution

Let E be the event of numbers to be divisible by 2 or 3.

$∴ E = {2, 3, 4, 6, 8, 9, 10, 12} \Rightarrow n (E) = 8 and n (S) = 12$

Hence, required probability $= \frac{n (E)}{n (S)} = \frac{8}{12} = \frac{2}{3}$

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