Two bodies of same material having masses ${\text{m}}_{\text{1}}\text{and}{\text{m}}_{\text{2}}$ are supplied equal amount of energy. Then the ratio of rise in temperature $\left(\frac{\Delta {\theta }_1}{\Delta {\theta }_2}\right)$ is equal to

Ratio of Temperature Rise for Two Bodies

Ratio of Rise in Temperature

Two bodies of the same material have masses m₁ and m₂, and both are supplied equal amounts of energy.

Calculation:

• Energy supplied, Q, leads to temperature rise: Q = mcΔθ
• For each: Q = m₁cΔθ₁ = m₂cΔθ₂
• Rearranging: m₁Δθ₁ = m₂Δθ₂
• Therefore: Δθ₁ / Δθ₂ = m₂ / m₁

Final Answer:

The ratio of rise in temperature is Δθ₁ / Δθ₂ = m₂ / m₁.