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Q.

Two identical copper spheres carrying charge+q and −9q separated by a certain distance d has an attractive force of F. If the spheres are allowed to touch each other and moved to distance of separation x so that force between them becomes4F9 then x is equal to

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a

d

b

2d

c

d2

d

4d

answer is B.

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Detailed Solution

F=14πε0q×9qd24F9=14πε0×4q×4qx2

94=9/d216x2

1=x24d2

x2=4d2

x=2d

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