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Q.

Two particles having mass ratio  n:1are interconnected by a light inextensible string that passes over a smooth pulley. If the system is released, then the acceleration of the centre of mass of the system is  

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a

(n+1n−1)2g

b

(n−1n+1)2g

c

(n+1n−1) g

d

(n−1)2g

answer is C.

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Detailed Solution

acm  = nma1–ma2(nm+m) = (n–1)(n+1)×a= (n–1)2(n+1)2g.

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