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Q.

Two point charges repel each other with a force of 100 N. One of the charges is increased by 10% and the other is reduced by 10%.The new force of repulsion at the same distance would be

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a

100 N

b

121 N

c

99 N

d

89 N

answer is C.

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Detailed Solution

100 = Kq1q2r2  and F=K(1.1q1)(0.9q2)r2

F100=0.99    ∴F=99N

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Two point charges repel each other with a force of 100 N. One of the charges is increased by 10% and the other is reduced by 10%.The new force of repulsion at the same distance would be