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Two radioactive sources A and B of half lives 1 hour and 2 hour respectively initially contain the same number of radioactive atoms. At the end of two hours, their rates of disintegration are ion the ratio of

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1:4

1:3

1:2

1:1

answer is C.

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Detailed Solution

Rate of disintegration $\propto$ No. of atoms left

In case of source A, $\frac{N}{N_{0}} = {(\frac{1}{2})}^{2} = \frac{1}{4}$

In case of source B, $\frac{N}{N_{0}} = {(\frac{1}{2})}^{1} = \frac{1}{2}$ .

$∴ \frac{R_{A}}{R_{B}} = \frac{N_{0} / 4}{N_{0} / 2} = \frac{1}{2}$

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