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Q.

Two 5 molal solutions are prepared by dissolving a non-electrolyte non-volatile solute separately in the solvents X and Y. The molecular weights of the solvents are Mx and MY, respectively where MX=0.75MY . The relative lowering of vapour pressure of the solution in X is ‘m’ times that of the solution in Y. Given that the number of moles of solute is very small in comparison to that of solvent, the value of ‘m’ is

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a

43

b

34

c

12

d

14

answer is B.

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Detailed Solution

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The relationship between two solvents' molar masses is MX=34MY(i) The relative vapour pressure reduction of two solutions is ΔPPX=mΔPPY However, the relative decrease in solution vapour pressure is directly  proportional to the mole fraction of solute. MR×51000=m×MY×51000..(ii) Replace equation (i) with equation (ii). 34×MY×51000=m×MY×51000m=34

Hence, the correct option is option (B) 34.

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