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Two ablocks of mass 2 kg are connected by a massless ideal spring of spring constant K = 10 N/m. The upper block is suspended from roof by a light string ‘A’. The system shown is in equilibrium. The string ‘A’ is now cut, the acceleration of upper block just after the string ‘A’ is cut will be (g = 10 m/s²)

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20 m/s²

10 m/s²

0 m/s²

15 m/s²

answer is B.

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Detailed Solution

Before the string A is cut, let x be elongation in the spring.

As system is in equilibrium

Then for lower block,

Kx = mg = 20 N

For upper block

ma = kx + mg

2a = 20 + 20

a = 20 m/s²

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