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Q.

Two bags together contain 50 chocolates. From the first bag, 12 chocolates were given to a child. Then 8 chocolates were taken from the first bag and put into the second bag to make the number of chocolates equal in both bags. How many chocolates were there in each bag? 


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a

35, 14

b

33, 17

c

40, 10

d

50, 0       

answer is B.

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Detailed Solution

Let bag A has x chocolates
And bag B has y chocolates
The number of chocolates in both bags is 50.
According to question
x + y = 50                --------------(i)
x - 8 = y + 8
x - y = 16              --------------(ii)
Now adding Eqn. (i) and Eqn. (ii) we get ‘
x + y + x- y = 50 + 16
2x = 66
x = 33
Now put  the value of x in Eqn. (i)
x + y = 50
33 + y = 50
y  = 17
Hence, Bag A has 33 chocolates and Bag B has 17 chocolates.   
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