Two balls A and B are thrown simultaneously from the top of a tower. A is thrown vertically up with a speed of $4 m s^{- 1} .$ B is thrown vertically down with a speed of $4 m s^{- 1} .$ The ball A and B hit the ground with speed $v_{A} a n d v_{B}$ respectively. Then,

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$v_{A} \geq v_{B}$

$v_{A} > v_{B}$

$v_{A} < v_{B}$

$v_{A} = v_{B}$

answer is D.

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Detailed Solution

When A returns to the level of top of tower, its downward velocity is $4 m s^{- 1} .$ This velocity is the same as that of B. So, both A and B hit the ground with the same velocity.

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