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Two balls are projected simultaneously with the same speed from the top of a tower - one upwards and the other downwards. If they reach the ground in 6s and 2s, the height of the tower is (g = 10 ms^–2)

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120m

60m

80m

30m

answer is B.

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Detailed Solution

$- h = 6 u - \frac{1}{2} g \times 36 h = 2 u + \frac{1}{2} g \times 4 H e n c e, 8 u = 16 g u = 20 m / s h = 60 m$

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