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Q.

Two balls of equal masses undergo a head-on collision with speeds $6 m / s$ moving in opposite direction. If the coefficient of restitution is $0.5,$ find the speed of each ball after impact in $m / s .$

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a

3

b

6

c

2

d

4

answer is A.

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Detailed Solution

$u_{1} = 6 \frac{m}{s}, u_{2} = - 6 \frac{m}{s}, 6 = 0.5 v_{1} = \frac{m_{1} - e m_{2}}{m_{1} + m_{2}} u_{1} + \frac{(1 + e) m_{2}}{m_{1} + m_{2}} u_{2} = (\frac{1 - 0.5}{2 m}) 6 m + \frac{(1 + 0.5) m}{2 m} (- 6) = \frac{0.5 \times 6}{2} + \frac{1.5}{2} (- 6) = 1.5 - 4.5 = - 3 \frac{m}{s}$

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Two balls of equal masses undergo a head-on collision with speeds 6 m/s moving in opposite direction. If the coefficient of restitution is 0.5, find the speed of each ball after impact in m/s.