Two balls of the same mass are shot upwards one after another at an interval of 2 seconds, along the same vertical line with the same initial velocity of 39.2 m/s. They will collide at a height :

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78.4 m.

44.1 m.

73.5 m.

58.5 m.

answer is C.

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Detailed Solution

When they collide displacement will be same but time of travel is t and t - 2.
$h = Ut - \frac{1}{2} {gt}^{2} = U (t - 2) - \frac{1}{2} g (t - 2)^{2}$
Solving t = 5 sec.
Substituting h = 73.5 m.

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