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Two bar magnets oscillate in a horizontal plane in earth’s magnetic field with time periods of 3s and 4s respectively. If their moments of inertia are in the ratio of 3:2, then the ratio of their magnetic moments will be

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2 : 1

8 : 3

1 : 3

27 : 16

answer is B.

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Detailed Solution

$\begin{array}{l} T = 2 π \sqrt{\frac{I}{M B_{H}}} \\ \frac{M_{1}}{M_{2}} = \frac{I_{1}}{I_{2}} \times {(\frac{T_{2}}{T_{1}})}^{2} = \frac{8}{3} \end{array}$

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