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Q.

Two batteries of e.m.f 4V and 8V with internal resistances 1Ω & 2Ω are connected in a circuit with a resistance of 9Ω as shown in figure. The current and potential difference between the points P and Q are 

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a

13A&3V

b

16A&4V

c

19A&9V

d

12A&12V

answer is A.

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Detailed Solution

For the cells in series

E = 8 – 4 = 4 

and i=EReff

⇒i=412=13A

Potential difference between points P and Q is

V=iR=13×9=3 V

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