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Q.

Two batteries E1 and E2 having emfs of 6V and 2V respectively and internal resistance of 2Ω and 3 Ω respectively are connected in parallel across a 5Ω resistor calculate. 
i) Current through each battery
ii) Terminal voltage
 

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a

1.23A, 3.55 V

b

1A, 5V

c

0.33 A, 3.3 V

d

0.5A, 7.3 V

answer is A.

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Detailed Solution

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Consider the loop HBCDEGH
Apply KVL 
2i16+23i2=02i13i2=4(1)

Consider ABHGEFA

3i22+5(i1+i2)=05i1+8i2=2(2)

Solving (1) & (2) we get

i1=2831=1.23Ai2=3.55A

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